Here, is my simple solution, how to protect the coil.
You can add a 1Ω/50Watt wire resistor in series with distribiteur....so the current will be limited by the resistor but the voltage will be the same.
more in the photos:
http://to4x4.gr/phpBB3/viewtopic.php?f=26&t=1676
DISTRIBITEUR COIL PROTECTION MWO Nr1
Moderators: rickf, raymond, Mr. Recovery
DISTRIBITEUR COIL PROTECTION MWO Nr1
Last edited by SV2IPW on April 10th, 2010, 3:54 pm, edited 1 time in total.
M-SERIES LOVER
M151A2 American Motors General 1977
(Hurricane L-142, 2320cc)
keep them rolling
T-99 16650
(O)IIII(O)
KEEP THEM ROLLING
M151A2 American Motors General 1977
(Hurricane L-142, 2320cc)
keep them rolling
T-99 16650
(O)IIII(O)
KEEP THEM ROLLING
- svramselaar
- Major
- Posts: 1109
- Joined: December 30th, 2007, 6:48 am
- Location: holland
Re: DISTRIBITEUR COIL PROTECTION
hello
the coil has a resistance about 6 ohm secondary
if the mutt is running the voltage a about 27 volts
the voltage at the coil go back 1/7 of 27 volt is 3.8 volt lower left 23.2 volt over the coil
the coil is 6 parts and the resistance 1 part of 27 volt 3.8 volt a part
the law of Ohm = volt = amp x resistance
in holland I =Amps U = Volts R = Ohm
U=I x R R = I : U I= R : U
also the amps go back from 4.5 till 3.8 amps
the ignition works as wen your generator is not working
the resistance will give 3.8 V x 3.8 Amp = 11.4 Watt on heat
greetings george
the coil has a resistance about 6 ohm secondary
if the mutt is running the voltage a about 27 volts
the voltage at the coil go back 1/7 of 27 volt is 3.8 volt lower left 23.2 volt over the coil
the coil is 6 parts and the resistance 1 part of 27 volt 3.8 volt a part
the law of Ohm = volt = amp x resistance
in holland I =Amps U = Volts R = Ohm
U=I x R R = I : U I= R : U
also the amps go back from 4.5 till 3.8 amps
the ignition works as wen your generator is not working
the resistance will give 3.8 V x 3.8 Amp = 11.4 Watt on heat
greetings george
Re: DISTRIBITEUR COIL PROTECTION
Υοu mean that the resistor wattage is too hi???
M-SERIES LOVER
M151A2 American Motors General 1977
(Hurricane L-142, 2320cc)
keep them rolling
T-99 16650
(O)IIII(O)
KEEP THEM ROLLING
M151A2 American Motors General 1977
(Hurricane L-142, 2320cc)
keep them rolling
T-99 16650
(O)IIII(O)
KEEP THEM ROLLING
- svramselaar
- Major
- Posts: 1109
- Joined: December 30th, 2007, 6:48 am
- Location: holland
Re: DISTRIBITEUR COIL PROTECTION
hello
no only tad the voltage at the coil go down with 3.8 volt and the max amps go down with 0.7 amps
the resistor can have the heat is is 50 watt and it gets 11.4 watt so it not melt down
the spark will be a bit lower as normal
i think a good coil go bad if let the ignition on and the engine not running
if the points are closed at tad time there will be a current over the coil 4.5 amps and it will burn out
the pointless electronic ignition i don t know if it set itself powerless (a new car do this ) otherwise the same as above
george
no only tad the voltage at the coil go down with 3.8 volt and the max amps go down with 0.7 amps
the resistor can have the heat is is 50 watt and it gets 11.4 watt so it not melt down
the spark will be a bit lower as normal
i think a good coil go bad if let the ignition on and the engine not running
if the points are closed at tad time there will be a current over the coil 4.5 amps and it will burn out
the pointless electronic ignition i don t know if it set itself powerless (a new car do this ) otherwise the same as above
george